Question

How do I use a boost::thread to execute a function with each thread executing in its own memory space. So that when I allocate a new variable with in the function it only lives as an instance in the executing thread.

Just to clarify I want to spawn threads that execute the same method using boost::thread but I do not want to use locks or semaphores I just want it to execute in a separate space.

Answer 1

Anything you allocate inside the thread function is already local to that function, as long as they’re not declared as static. Just write your code as normal (avoiding static local variables) and you’ll be fine.