Question

How do I use the OpenFileDialog class (in C#, WPF etc.) such that it opens on the Network area as default?

This does not work:

  OpenFileDialog openFileDialog1 = new OpenFileDialog();
  openFileDialog1.InitialDirectory = "Network";

I also tried having “\” as an InitialDirectory and that did not work.

I also tried having “\\” as an InitialDirectory and that did not work either.

Answer 1

I haven’t tried it, but this should work:

openFileDialog1.InitialDirectory = Environment.GetFolderPath(Environment.SpecialFolder.NetworkShortcuts);

Environment.GetFolderPath returns the path corresponding to an Environment.SpecialFolder enumeration entry as a string.

Environment.SpecialFolder.NetworkShortcuts is defined as

A file system directory that contains
the link objects that may exist in the
My Network Places virtual folder.