Question

How do I use this Java regular expression ("\\d+\\.*\\d+"); in the Oracle regexp_replace function. This is working fine in Java, but with Oracle, it is not working.

Example data:

<Tier><grade><><sdlc><17,10><> : result should be 17.10
<><sdlc><16,909312> : 16.909312
<><sdlc><11396,87> : 11396.87
<20121217> : 20121217
<UNIT><6086> : 6086
<Tier1><><sdlc><0,47> : 0.47

Answer 1

Use replace then regexp_substr followed by translate rather than using regexp_replace:

select translate(regexp_substr(replace(str, ',>', '>')
        , '<[[:digit:]]+(,[[:digit:]]*)?>')
    , ',<>', '.')
from so

sqlfiddle

From Oracle Database SQL Language Reference 11g Release 2 (11.2):

• TRANSLATE
• REPLACE
• REGEXP_SUBSTR
• Oracle Regular Expression Support