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Home/ Questions/Q 8057003
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T08:53:26+00:00 2026-06-05T08:53:26+00:00

How do I write an XSLT template that takes all non meta and answer

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How do I write an XSLT template that takes all non “meta” and “answer” elements and deposits them into a “my_question” template? So, for example, given the below XML …

<question>
    <meta>
        ...
    </meta>
    <para />
    <para>Why?</para>
    <answer weight="1" correctness="0">
        ...
    </answer>
    <answer weight="1" correctness="0">
        ...
    </answer>
    <answer weight="1" correctness="100">
        ...
    </answer>
    <answer weight="1" correctness="0">
        ...
    </answer>
</question>

I would want the result to be

<my_question>
    <para />
    <para>Why?</para>        
</my_question>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-05T08:53:27+00:00Added an answer on June 5, 2026 at 8:53 am

    The identity template is your friend

    <xsl:stylesheet
     xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
     version="2.0">
    
     <xsl:output method="xml" encoding="utf-8" indent="yes"/>
    
     <xsl:template match="/">
         <my_question>
            <xsl:apply-templates select="question"/>
         </my_question>
     </xsl:template>
    
     <!-- ignores the specified elements. Adjust for nesting if necessary. -->
     <xsl:template match="meta | answer"/>
    
     <!-- Pass everything else -->
     <xsl:template match="@*|node()">
     <xsl:copy>
        <xsl:apply-templates select="@*|node()"/>
     </xsl:copy>
     </xsl:template>
    </xsl:stylesheet>
    
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