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Home/ Questions/Q 7435151
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T10:00:58+00:00 2026-05-29T10:00:58+00:00

How do you convert this jquery code to plain JavaScript (i.e. Remove jquery dependency)?

  • 0

How do you convert this jquery code to plain JavaScript (i.e. Remove jquery dependency)?

Inside the <head> of app.html

<script src="http://code.jquery.com/jquery-1.7.1.min.js"></script>

<script type="text/javascript">
   var textToSend = "blah blah";
   var moreText = "yada yada yada";
   $.post( "process.php", { text1: textToSend, text2: moreText},
      function( data ) {
         alert("Process.php script replies : " + data);
      }
   );
</script>

process.php is in the same folder on the server.

<?php
   print "<p>You said " . $_POST['text1'] . "</p>";
   print "<p>Then you added " . $_POST['text2'] . "</p>";
?>

Forgive my newbie vagueness.
Thanks in advance.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-29T10:00:59+00:00Added an answer on May 29, 2026 at 10:00 am

    Try this.

    <script type="text/javascript">
    function doPost()
    {
        var textToSend = "blah blah";
       var moreText = "yada yada yada";
        var xmlhttp;
        if (window.XMLHttpRequest)
      {// code for IE7+, Firefox, Chrome, Opera, Safari
      xmlhttp=new XMLHttpRequest();
      }
        else
      {// code for IE6, IE5
      xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
      }
        xmlhttp.onreadystatechange=function()
      {
      if (xmlhttp.readyState==4 && xmlhttp.status==200)
        {
         alert("Process.php script replies : " + xmlhttp.responseText);
    
        }
      }
    xmlhttp.open("POST","process.php",true);
    xmlhttp.setRequestHeader("Content-type","application/x-www-form-urlencoded");
    xmlhttp.send("text1=" + encodeURIComponent(textToSend) + "&text2=" + encodeURIComponent(moreText) );
    }
    </script>
    

    EDIT: I added encodeURIComponent() function to encode the parameters.

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