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Home/ Questions/Q 608667
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T17:29:06+00:00 2026-05-13T17:29:06+00:00

How do you declare a class property as an object? I tried: public $objectname

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How do you declare a class property as an object?

I tried:

 public $objectname = new $Object();

But it didn’t work. Additionally, why should you do it like that?

Isn’t it better to just instantiate that object and just use its members?

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  1. Editorial Team
    Editorial Team
    2026-05-13T17:29:06+00:00Added an answer on May 13, 2026 at 5:29 pm

    From the PHP manual on class properties (emphasis mine):

    Class member variables are called "properties". You may also see them referred to using other terms such as "attributes" or "fields", but for the purposes of this reference we will use "properties". They are defined by using one of the keywords public, protected, or private, followed by a normal variable declaration. This declaration may include an initialization, but this initialization must be a constant value –that is, it must be able to be evaluated at compile time and must not depend on run-time information in order to be evaluated.

    Either create it inside the constructor (composition)

    class Foo
    {
        protected $bar;
        public function __construct()
        {
            $this->bar = new Bar;   
        }
    }
    

    or inject it in the constructor (aggregation)

    class Foo
    {
        protected $bar;
        public function __construct(Bar $bar)
        {
            $this->bar = $bar;   
        }
    }
    

    or use setter injection.

    class Foo
    {
        protected $bar;
        public function setBar(Bar $bar)
        {
            $this->bar = $bar
        }
    }
    

    You want to favor aggregation over composition.

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