Home/ Questions/Q 98459
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Asked: 2026-05-11T00:12:00+00:00

How do you do it? Given a byte array: byte[] foo = new byte[4096];

  • 0

How do you do it? Given a byte array:

byte[] foo = new byte[4096];

How would I get the first x bytes of the array as a separate array? (Specifically, I need it as an IEnumerable<byte>)

This is for working with Sockets. I figure the easiest way would be array slicing, similar to Perls syntax:

@bar = @foo[0..40];

Which would return the first 41 elements into the @bar array. Is there something in C# that I’m just missing, or is there some other thing I should be doing?

LINQ is an option for me (.NET 3.5), if that helps any.

Share

Leave an answer

You must login to add an answer.

Need An Account,

1 Answer

  1. Arrays are enumerable, so your foo already is an IEnumerable<byte> itself. Simply use LINQ sequence methods like Take() to get what you want out of it (don’t forget to include the Linq namespace with using System.Linq;):

    byte[] foo = new byte[4096];  var bar = foo.Take(41);

    If you really need an array from any IEnumerable<byte> value, you could use the ToArray() method for that. That does not seem to be the case here.

    • 0