Question

How do you download, resize and store an image from a remote server using php?
This is the code I am using

$temp_image = file_get_contents($url);
$image = imagecreatefromstring($temp_image);
$thumb = imageToCanvas($image,100,75,true);
imagejpeg($thumb,$base_image_path . $thumb_path,90)


function imageToCanvas($_image, $_canvasWidth, $_canvasHeight, $forceScale=false,$x=false,$y=false) 
{
    $newImage = imagecreatetruecolor($_canvasWidth, $_canvasHeight);
    $imageinfo = getimagesize($_image);
    $sourceWidth = $imageinfo[0];
    $sourceHeight = $imageinfo[1];  
    $sourceImage = openImage($_image);
    imagecopyresampled($newImage, $sourceImage, 0, 0, 0, 0, $_canvasWidth, $_canvasHeight, $sourceWidth, $sourceHeight);
    return $newImage;
}

function openImage($file) 
{
 // *** Get extension
 $extension = strtolower(strrchr($file, '.'));
 switch($extension) {
   case '.jpg': case '.jpeg':
     $img = @imagecreatefromjpeg($file);
     break;
   case '.gif':
    $img = @imagecreatefromgif($file);
     break;
   case '.png':
     $img = @imagecreatefrompng($file);
     break;
   default:
     $img = false;
     break;
 }
 return $img; 
}

Doesn’t work and I don’t know why.

$sourceWidth & $sourceHeight doesn’t have a value so I presume $image is in the wrong format

Thanks!

Answer 1

There is no function in php called openImage so that would be a problem if you don’t define it yourself.

If you do have it defined, what does it look like and are you receiving any errors?

Edit: Based on your comments the problem would seem to be that you treat the input parameter of your openImage function as a file path. However, when you call it you are feeding it an image resource, the result of imagecreatefromstring.