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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T08:51:49+00:00 2026-05-15T08:51:49+00:00

How do you read a csv file into a two dimensional array in BASH?

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How do you read a csv file into a two dimensional array in BASH? The script needs to be dynamic enough where it can take csv files with variable number of rows and columns.

For example, if I have a csv file that looks like

AVERAGE     STDEV     MAX
17          18        19

or

AVERAGE     STDEV     MAX     MIN
17          18        19      1
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  1. Editorial Team
    Editorial Team
    2026-05-15T08:51:50+00:00Added an answer on May 15, 2026 at 8:51 am

    One way to simulate a two-dimensional array is to keep the rows as strings in a one-dimensional array and unpack them at each iteration. You will have to choose a suitable delimiter that doesn’t appear in the data. Since you mention CSV, I’ll use a comma, but this won’t be smart enough to handle data like this with embedded commas:

    name, start date, visits, games, balance
    "Williamson, Dennis", "January 11, 2007", 12, 42, 17000
    

    Here’s a simple example of iterating over the values in a simulated two-dimensional array:

    # avg, stddev, max, min
    data_array=(
                "17,18,19,1"
                "12,14,16,2"
                "6,8,10,3"
                )
    
    saveIFS=$IFS
    
    for row in ${data_array[@]}
    do
        IFS=","
        cols=($row)
        IFS=$saveIFS
        for col in ${cols[@]}
        do
            newval=$(do_something $col)
        done
    done
    

    Making changes to the contents of the array is possible:

    rowidx=2
    colidx=2
    IFS=","
    cols=(${data_array[rowidx]})
    cols[colidx]=$some_value
    data_array[rowidx]="${cols[*]}"
    IFS=$saveIFS
    

    As you can see, it gets complicated fast and there are lots of gotchas which I haven’t mentioned. Use Python.

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