Question

How do you turn a String input into an int array of [][]

Like for example if i have an input of 3a then it should return back to the index of [2][0] and if it have like 5e then it should go to the index of [4][4]

Answer 1

Like this:

public static void main(String[] args) {
    int[][] array;

    array = createArray("3a");
    System.out.println(array.length + "," + array[0].length);

    array = createArray("5e");
    System.out.println(array.length + "," + array[0].length);

    array = createArray("9g");
    System.out.println(array.length + "," + array[0].length);
}

private static int[][] createArray(String input) {
    int a = Integer.parseInt(input.substring(0, 1)) - 1;
    int b = input.charAt(1) - 97;
    return new int[a][b];
}

This outputs:

2,0
4,4
8,6

Also make sure to do some method of validation on the input before passing it into createArray. A simple regex pattern would do the trick for that: [0-9][a-z].