Question

How does django-admin resolves model from url?

I takes url like this “/admin/video/item/”

How can I do the same? Get model from that url…

I need to implement function which gets ‘/admin/vide/item’ and returns Item object in video app.

Update:

I can easily turn ‘admin/video/items’ to video.models.Item but im not sure if first later in model name is uppercase or there can be more uppercase laters.

Documentation says:

view, args, kwargs = urlresolvers.resolve('/admin/video/item/')
enter code hereview(*args,**kwargs)

so i have view right? The next question how do i get model from that view?

Answer 1

The admin urls consist of the app label and the model name.

You can use django.db.models.get_model to get a model class from those two strings.

# urls
(r'^admin/(?P<app_label>\w+)/(?P<model_name>\w+)/$', my_view),

# view
from django.db.models import get_model

def my_view(request, app_label, model_name):
    model_class = get_model(app_label, model_name)
    return http.HttpResponse(model_class.objects.all())