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Asked: May 11, 20262026-05-11T01:35:52+00:00 2026-05-11T01:35:52+00:00

How does Python evaluate the expression 1+++2 ? How many ever + I put

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How does Python evaluate the expression 1+++2?

How many ever + I put in between, it is printing 3 as the answer. Please can anyone explain this behavior

And for 1--2 it is printing 3 and for 1---2 it is printing -1

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  1. 2026-05-11T01:35:53+00:00Added an answer on May 11, 2026 at 1:35 am

    Your expression is the same as:

    1+(+(+2)) 

    Any numeric expression can be preceded by - to make it negative, or + to do nothing (the option is present for symmetry). With negative signs:

    1-(-(2)) = 1-(-2)          = 1+2          = 3 

    and

    1-(-(-2)) = 1-(2)           = -1 

    I see you clarified your question to say that you come from a C background. In Python, there are no increment operators like ++ and -- in C, which was probably the source of your confusion. To increment or decrement a variable i or j in Python use this style:

    i += 1 j -= 1 
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