Question

How does the compiler control protection of variables in memory? Is there a tag bit associated with private variables inside the memory? How does it work?

Answer 1

If you mean private members of instances, then there’s no protection whatsoever at run-time. All protection takes place at compile-time and you can always get at the private members of a class if you know how they are laid out in memory. That requires knowledge of the platform and the compiler, and in some cases may even depend on compiler settings such as the optimization level.

E.g., on my Linux/x86-64 w/GCC 4.6, the following program prints exactly what you expect. It is by no means portable and might print unexpected things on exotic compilers, but even those compilers will have their own specific ways to get to the private members.

#include <iostream>

class FourChars {
  private:
    char a, b, c, d;

  public:
    FourChars(char a_, char b_, char c_, char d_)
      : a(a_), b(b_), c(c_), d(d_)
    {
    }
};

int main()
{
    FourChars fc('h', 'a', 'c', 'k');

    char const *p = static_cast<char const *>(static_cast<const void *>(&fc));

    std::cout << p[0] << p[1] << p[2] << p[3] << std::endl;
}

(The complicated cast is there because void* is the only type that any pointer can be cast to. The void* can then be cast to char* without invoking the strict aliasing rule. It might be possible with a single reinterpret_cast as well — in practice, I never play this kind of dirty tricks, so I’m not too familiar with how to do them in the quickest way 🙂