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Home/ Questions/Q 9071455
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Editorial Team
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Editorial Team
Asked: June 16, 20262026-06-16T17:55:08+00:00 2026-06-16T17:55:08+00:00

How I can implement a server in Go, which sends each incomming line to

  • 0

How I can implement a server in Go, which sends each incomming line to stdout ?

package main

import (
    "io"
    "log"
    "net"
)

func main() {
    srv, err := net.Listen("tcp", ":2000")
    for {
        conn, err := srv.Accept()
        go func(c net.Conn) {

            //How to split here by lines ?

            c.Close()
        }(conn)
    }
}

After runing the server with

./server

And running telnet

telnet localhost 2000
Trying 127.0.0.1...
Connected to localhost.
Escape character is '^]'.
test 123
foobar

I want to see on stdout where I started the server:

test 123
foobar

I know this code lacks error handling, but this is only for clearity to show what I’m trying to do.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-16T17:55:09+00:00Added an answer on June 16, 2026 at 5:55 pm

    Since a net.Conn is an io.Reader, you can wrap it in a bufio.Reader and use the ReadString method on that type. Your function would become

    func(c net.Conn) {
        f := bufio.NewReader(c)
        for {
            ln, err := f.ReadString('\n')
            if err == io.EOF {
                break
            } else if err != nil {
                panic(err)
            }
            fmt.Print(ln)
        }
        c.Close()
    }
    

    (I’m not sure if stdout is synchronized in Go; it might be cleaner to send the lines on a shared channel that is looped over in a separate goroutine.)

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