Question

How i return iterator form function :

i worte this :
.
..

template<class S,class T> class Database {
public:
.
..
 map<S,Node<T>*> m_map::iterator Find (S keyToFind);
.
..
....


private:
.
..
 map<S,Node<T>*> m_map;
..
.
};

.
..
template<class S,class T>
map<S,Node<T>*> m_map::iterator Find (S keyToFind) {
 map<S,Node<T>*>::iterator itMap;
 itMap = m_map.find(KeyToUpDate);
 return itMap;
}
..
.

there are many error because this :
Error 1 error C2653: ‘m_map’ : is not a class or namespace name
Error 2 error C2146: syntax error : missing ‘;’ before identifier ‘Find’
Error 3 error C4430: missing type specifier – int assumed. Note: C++ does not support default-
Error 5 error C2653: ‘m_map’ : is not a class or namespace name
Error 7 error C2133: ‘iterator’ : unknown size
..
…

i don’t understand what is the problem..

Answer 1

This should be:

template<class S,class T>
typename map<S,Node<T>*>::iterator Find(S keyToFind) {
    typename map<S,Node<T>*>::iterator itMap;
    itMap = m_map.find(KeyToUpDate);
    return itMap;
}

and

typename map<S,Node<T>*>::iterator Find (S keyToFind);

typename is needed because iterator is a dependent type, see e.g. here.