How is C++ supposed to print negative values in base 8 or 16? I know I can try what my current compiler/library does (it prints the bit pattern, without a minus in front) but I want to know what is should do, preferrably with a reference.
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How is C++ supposed to print negative values in base 8 or 16? I know I can try what my current compiler/library does (it prints the bit pattern, without a minus in front) but I want to know what is should do, preferrably with a reference.
From §22.2.2.2.2 (yes, really) of n1905, using
ios_base::hexis equivalent to thestdioformat specifier%xor%X.From §7.21.6.1 of n1570, the
%xspecifier interprets its argument as an unsigned integer.(Yes, I realize that those are wacky choices for standards documents. I’m sure you can find the text in your favorite copy if you look hard enough.)