Question

How is it possible to give a function (B) a function (A) as a parameter?

So that I can use function A in the function B.

Like the Variable B in the following example:

foo(int B) { ... }

Answer 1

write function pointer type in another function’s parameter list looks a little weird, especially when the pointer is complicated, so typedef is recommended.

EXAMPLE

#include <stdio.h>

typedef int func(int a, int b);

int add(int a, int b) { return a + b; }

int operate(int a, int b, func op)
{
    return op(a, b);
}

int main()
{
    printf("%d\n", operate(3, 4, add));
    return 0;
}