Question

How it works: Clicking on the album will take you to “album.php?id=#”

//initialize some vars
$albumID = '';

//check what photo we are looking for
if(isset($_GET['id'])){
    $albumID = mysql_real_escape_string($_GET['id']);

Query:

$sql = mysql_query(
SELECT *
FROM albums
JOIN songs
ON albums.performer=songs.performer
WHERE albums.albumID='albumID'
);

What I was trying to accomplish is have it display the album and tracklist. Does anybody know how I should fix this problem? Thank you.

Answer 1

Start by placing your query in a string:

$query = "SELECT * FROM albums JOIN songs ON albums.performer=songs.performer";

Then, if an album is present, add to that query:

if ( !empty( $albumID ) ) {
  $query = $query . " WHERE albums.albumID = $albumID";
}

At this point, we can go ahead and run the query:

$result = mysql_query( $query ) or die( mysql_error() );

We run the query, using mysql_query, and pass its results into the $result variable. If anything goes wrong, like an error in our query, our program will die, and the most recent mysql_error() will be printed to the screen.

With our $result variable, we can now cycle through and print the results:

while ( $row = mysql_fetch_object( $result ) ) {
  echo $row->columnA
}

Note that columnA is a placeholder, where you should actually write the column name(s) you have stored in your database.