Question

How the static constructor is behaving here ?

class a
{    
    public static int x;
    static a()
    {
        x = b.y + 1;    
    }
}

class b    
{    
    public static int y = a.x + 1;

    static b()
    { 

    }

    static void Main(String[] args)
    {
       Console.WriteLine("x={0} , y={1} ", a.x, b.y);
        Console.ReadLine();    
    }
}

Output ::

x=1 , y=2

How ?

Answer 1

This is, except for case, the exact example given here, which gives the following explanation:

To execute the Main method, the system first runs the initializer for B.Y, prior to class B’s static constructor. Y’s initializer causes A’s static constructor to be run because the value of A.X is referenced. The static constructor of A in turn proceeds to compute the value of X, and in doing so fetches the default value of Y, which is zero. A.X is thus initialized to 1. The process of running A’s static field initializers and static constructor then completes, returning to the calculation of the initial value of Y, the result of which becomes 2.