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Home/ Questions/Q 8732085
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T09:22:27+00:00 2026-06-13T09:22:27+00:00

How to add ID to GridView rows (IDs should be rendered)? I am using

  • 0

How to add ID to GridView rows (IDs should be rendered)?

I am using .NET (C#). I have GridView control.

I have some javascript functions that are manipulating table rows, but it is necessary to have IDs for those rows:

<table>
    <tr id=1> ...  
    <tr id=2> ...  //id should come from database
..

My GridView is genereted from Data from DataBase. It is important not to have FAKE ROW IDS, but really row ids from DB (there are some ajax javascript function that updates DB based on those IDs and user manipulations with table).

Part of my GridView is the following:

  <asp:GridView ID="grdNews" runat="server" BorderStyle="None" RowStyle-BorderStyle="None"
                GridLines="None" CssClass="table" Style="white-space: nowrap" AutoGenerateColumns="False"
                DataKeyNames="ID" AllowSorting="True" AllowPaging="true" OnSorting="grdNews_Sorting" OnRowDataBound="grdNews_RowDataBound">
                <RowStyle BorderStyle="None" />
                <HeaderStyle CssClass="nodrag" />
                <Columns>
                ....

I have tried the following:

 protected void grdNews_RowDataBound(object sender, GridViewRowEventArgs e)
{
     if (e.Row.RowType == DataControlRowType.DataRow)
     {
         e.Row.ID = grdNews.DataKeys[e.Row.RowIndex].Value.ToString();
     }
}

This gives e.Row.ID the correct value, but this doesn’t render this ID.

So, how to render IDs from DataBase for Rows in GridView?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-13T09:22:28+00:00Added an answer on June 13, 2026 at 9:22 am

    Try following….

    protected void grdNews_RowDataBound(object sender, GridViewRowEventArgs e)
     {
          if (e.Row.RowType == DataControlRowType.DataRow)
          {
            GridViewRow row = e.Row;
            row.Attributes["id"] =grdNews.DataKeys[e.Row.RowIndex].Value.ToString();
    
    
          }
     } 
    
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