Question

How to build all sequential of a table field value in SQL Server
i have a table similar this

a
b
b
c
d 
f

i need a function for this table with similar output

a
ab
abb
abbc
abbcd
abbdcf

Assuming i have a ID that orders those items.

Answer 1

Assuming you have a (gapless, increasing) ID that orders those items:

with tree (id, all_items) as (
  select id, cast(data as varchar(max)) as all_items
  from foo 
  where id = 1

  union all

  select c.id, p.all_items + c.data
  from foo c
    join tree p on p.id = c.id - 1
)
select all_items
from tree

SQLFiddle example: http://www.sqlfiddle.com/#!3/8840c/1