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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T08:52:25+00:00 2026-06-11T08:52:25+00:00

How to convert python list into JSON format with just using the basic tools

  • 0

How to convert python list into JSON format with just using the basic tools and utilities and include the specific “name”, “group”, “source”, “target” key names etc? Is it basically alot of string concatenations to construct that format?

The list index represent connectivity, for example index 0 in the list connects to index 1, 3, 4, 5, 6, 7, 8, 9 and 1 connects to 0, 2, 3, 4, 5, 6, 7, 8, 9

List:

[[1, 3, 4, 5, 6, 7, 8, 9], [0, 2, 3, 4, 5, 6, 7, 8, 9], [1, 3, 4, 7, 9], [0, 1, 2, 4, 5, 6, 7, 9], [0, 1, 2, 3, 6, 7, 8], [0, 1, 3, 6, 7, 8, 9], [0, 1, 3, 4, 5, 7, 8, 9], [0, 1, 2, 3, 4, 5, 6, 8, 9], [0, 1, 4, 5, 6, 7, 9], [0, 1, 2, 3, 5, 6, 7, 8]]

Into something like this JSON format?

    {"nodes":
[
{"name":"Zone1","group":0},
{"name":"Zone2","group":1},
{"name":"Zone3","group":2},
{"name":"Zone4","group":3},
{"name":"Zone5","group":4},
{"name":"Zone6","group":5},
{"name":"Zone7","group":6},
{"name":"Zone8","group":7},
{"name":"Zone9","group":8},
{"name":"Zone10","group":9}
],
"links":[
{"source":0,"target":1},
{"source":0,"target":3},
{"source":0,"target":4},
{"source":0,"target":5},
{"source":0,"target":6},
{"source":0,"target":7},
{"source":0,"target":8},
{"source":0,"target":9},
{"source":1,"target":0},
{"source":1,"target":2},
{"source":1,"target":3},
{"source":1,"target":4},
{"source":1,"target":5},
{"source":1,"target":6},
{"source":1,"target":7},
{"source":1,"target":8},
{"source":1,"target":9},
{"source":2,"target":1},
{"source":2,"target":3},
{"source":2,"target":4},
{"source":2,"target":7},
{"source":2,"target":9},
{"source":3,"target":0},
{"source":3,"target":1},
{"source":3,"target":2},
{"source":3,"target":4},
{"source":3,"target":5},
{"source":3,"target":6},
{"source":3,"target":7},
{"source":3,"target":9},
{"source":4,"target":0},
{"source":4,"target":1},
{"source":4,"target":2},
{"source":4,"target":3},
{"source":4,"target":6},
{"source":4,"target":7},
{"source":4,"target":8},
{"source":5,"target":0},
{"source":5,"target":1},
{"source":5,"target":3},
{"source":5,"target":6},
{"source":5,"target":7},
{"source":5,"target":8},
{"source":5,"target":9},
{"source":6,"target":0},
{"source":6,"target":1},
{"source":6,"target":3},
{"source":6,"target":4},
{"source":6,"target":5},
{"source":6,"target":7},
{"source":6,"target":8},
{"source":6,"target":9},
{"source":7,"target":0},
{"source":7,"target":1},
{"source":7,"target":2},
{"source":7,"target":3},
{"source":7,"target":4},
{"source":7,"target":5},
{"source":7,"target":6},
{"source":7,"target":8},
{"source":7,"target":9},
{"source":8,"target":0},
{"source":8,"target":1},
{"source":8,"target":4},
{"source":8,"target":5},
{"source":8,"target":6},
{"source":8,"target":7},
{"source":8,"target":9},
{"source":9,"target":0},
{"source":9,"target":1},
{"source":9,"target":2},
{"source":9,"target":3},
{"source":9,"target":5},
{"source":9,"target":6},
{"source":9,"target":7},
{"source":9,"target":8}
]}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-11T08:52:26+00:00Added an answer on June 11, 2026 at 8:52 am

    Guessing from inputs and outputs, here is probably what you want.

    import json
    def convert(adj_lst):
        links = []
        for i,adj in enumerate(adj_lst):
            links.extend( [{'source':i,'target':n} for n in adj] )
        nodes = [{"name":"Zone%d" % i, "group":i} for i in xrange(len(adj_lst))]
        return {"nodes":nodes, "links":links}
    
    adj_list = [[1, 3, 4, 5, 6, 7, 8, 9], [0, 2, 3, 4, 5, 6, 7, 8, 9], [1, 3, 4, 7, 9], [0, 1, 2, 4, 5, 6, 7, 9], [0, 1, 2, 3, 6, 7, 8], [0, 1, 3, 6, 7, 8, 9], [0, 1, 3, 4, 5, 7, 8, 9], [0, 1, 2, 3, 4, 5, 6, 8, 9], [0, 1, 4, 5, 6, 7, 9], [0, 1, 2, 3, 5, 6, 7, 8]]
    print json.dumps(convert(adj_list), indent=2)
    
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