Question

How to create a partitioned index on a table which is not partitioned although there is a partition function and scheme available. It is an exercise I read somewhere, not a real problem

create partition function func(datetime)
as range right for values
('20040601', '20050601')
go
create partition scheme scheme1
as partition func
to ('primary')
go

create table student
(
studentid int not null primary key nonclustered,
firstname varchar(30) not null,
date datetime not null
)

i was thinking of

create clustered index IX_StudentID_Date
on student(studentid, date)

but the table is not partitioned, so how to create the index, without partitioning the table?

Answer 1

When you partition the “table” you are actually partitioning the clustered index. So partitioning a non clustered index is actually the same as partitioning a “table”

    CREATE NONCLUSTERED INDEX IX_StudentID_Date 
        ON student(studentid, date) 
        ON scheme1(date)   

you just have to make sure that the partition field is part of the index.