Question

How to cut part from this string…

"abb.c.d+de.ee+f.xxx+qaa.+.,,s,"

… where i know position by this:

Result is always between “.” (left side of result) and “+” (right side).
I know number of “.” from left side and number of “+” from right side, to delimit resulting string.

Problem is right side, cause i need to count “+” from end.

Say…

from left side: begining is at 4th “.”
( this is easy ), result is =

"xxx+qaa.+.,,s,"

from right side: end is at second “+” from end!

"xxx[here]+qaa.+.,,s,"

result is =

"xxx"

I try to do this myself with .substring and .indexOf, but with no success…

Any ideas? thanks

Answer 1

You could use the StrReverse function to reverse the character sequence and then count + from the left (using the same method as counting the .).