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Home/ Questions/Q 4618344
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T02:15:13+00:00 2026-05-22T02:15:13+00:00

How to declare an iterator to std::map <T, Point <T> *> , where: template

  • 0

How to declare an iterator to

std::map <T, Point <T> *> ,

where:

template <typename T>
struct TList
{
    typedef std::vector < std::map <T, Point <T> *> >  Type;
};

In the following code

int main ()
{
    ....
    std::map <T, Point <T> *> ::iterator i_map;  //Error
    ...
}

g++ shows this error:

error: dependent-name `  std::map<T,Point<T>*,std::less<_Key>,std::allocator<std::pair<const T, Point<T>*> > >::iterator' is parsed as a non-type, but instantiation yields a type
note: say `typename  std::map<T,Point<T>*,std::less<_Key>,std::allocator<std::pair<const T, Point<T>*> > >::iterator' if a type is meant
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-22T02:15:14+00:00Added an answer on May 22, 2026 at 2:15 am

    Use typename as:

      typename std::map<T, Point <T> *>::iterator i_map;
    //^^^^^^^^ here!
    

    Because iterator is a dependent-name (as it depends on the map’s type argument T), so typename is required here.

    Read this FAQ for detail explanation:

    Where and why do I have to put the "template" and "typename" keywords?

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