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Home/ Questions/Q 6627903
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T22:04:06+00:00 2026-05-25T22:04:06+00:00

How to define a rotates function that generates all rotations of the given list?

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How to define a rotates function that generates all rotations of the given list?

For example: rotates [1,2,3,4] =[[1,2,3,4],[2,3,4,1],[3,4,1,2],[4,1,2,3]]

I wrote a shift function that can rearrange the order

 shift ::[Int]->[Int]

 shift x=tail ++ take 1 x

but I don’t how to generate these new arrays and append them together.

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  1. Editorial Team
    Editorial Team
    2026-05-25T22:04:06+00:00Added an answer on May 25, 2026 at 10:04 pm

    The following

    shift :: [a] -> Int -> [a]
    shift l n = drop n l  ++ take n l
    
    allRotations :: [a] -> [[a]]
    allRotations l = [ shift l i | i <- [0 .. (length l) -1]]
    

    yields

    > ghci
    Prelude> :l test.hs
    [1 of 1] Compiling Main             ( test.hs, interpreted )
    Ok, modules loaded: Main.
    *Main> allRotations [1,2,3,4]
    [[1,2,3,4],[2,3,4,1],[3,4,1,2],[4,1,2,3]]
    

    which is as you expect.

    I think this is fairly readable, although not particularly efficient (no memoisation of previous shifts occurs).


    If you care about efficiency, then

    shift :: [a] -> [a]
    shift [] = []
    shift (x:xs) = xs ++ [x]
    
    allRotations :: [a] -> [[a]]
    allRotations l = take (length l) (iterate shift l)
    

    will allow you to reuse the results of previous shifts, and avoid recomputing them.

    Note that iterate returns an infinite list, and due to lazy evaluation, we only ever evaluate it up to length l into the list.


    Note that in the first part, I’ve extended your shift function to ask how much to shift, and I’ve then a list comprehension for allRotations.

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