Question

How to get all nodes present in jsTree?

I am building jsTree with xml

Root
     -----A
          -----A1
               -----A1.1
               -----A1.2
          -----A2
               -----`A2.1`
               -----A2.2

     -----B
          -----B1
          -----B2

     -----C
          -----C1
               -----C1.1
               -----C2.2

I want array of all nodes(ID) present in jsTree is as follows

Expected output: [Root, A, A1, A1.1, A1.2, A2, A2.1, A2.2, B, B1, B2, C, C1, C1.1, C2.2]

Answer 1

Solution with example 🙂

var xmlString = $("#tree").jstree("get_xml");   
    var xmlDOM = $.parseXML(xmlString);

    var IDList =[];
var items = $(xmlDOM).find('root item');
$.each (items, function(key, val){
    IDList.push($(val).attr('id'));
})

IDList.pop();

xmlString =

<root>  
        <item id="A" parent_id="0" state="close">  
            <content><name>Charles Madigen</name></content>                
        </item>
        <item id="A1" parent_id="A" state="close">  
            <content><name>Charles Madigen</name></content>                
        </item>
          .
          .
</root>

Output: Root, A, A1, A1.1, A1.2, A2, A2.1, A2.2, B, B1, B2, C, C1, C1.1, C2.2

🙂