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Home/ Questions/Q 8800785
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T00:40:52+00:00 2026-06-14T00:40:52+00:00

How to get non-trivial solution for such equation with Numpy? r1 = r1 *

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How to get non-trivial solution for such equation with Numpy?

r1 = r1 * 0.03  + r2 * 0.88 + r3 * 0.2425 + r4 * 0.03 + r5 * 0.03
r2 = r1 * 0.455 + r2 * 0.03 + r3 * 0.2425 + r4 * 0.03 + r5 * 0.88
r3 = r1 * 0.455 + r2 * 0.03 + r3 * 0.03   + r4 * 0.03 + r5 * 0.03
r4 = r1 * 0.03  + r2 * 0.03 + r3 * 0.2425 + r4 * 0.03 + r5 * 0.03
r5 = r1 * 0.03  + r2 * 0.03 + r3 * 0.2425 + r4 * 0.88 + r5 * 0.03
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  1. Editorial Team
    Editorial Team
    2026-06-14T00:40:54+00:00Added an answer on June 14, 2026 at 12:40 am

    If you’re just looking for a library function that does this, just use numpy.linalg.eig and look for the eigenvector with eigenvalue equal to 1. If you need to implement an iterative solver, probably the power method is the best idea for this. It should simply work because the vector with eigenvalue of 1 is also the one with largest eigenvalue. Krylov subspace method (Rayleigh iteration) should work well on this too.

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