Question

How to get the double value that is only two digit after decimal point.

For example if the a = 190253.80846153846
then the result value should be like a = 190253.80

Try:
I have try with this:

public static DecimalFormat twoDForm = new DecimalFormat("#0.00");

in code

a = Double.parseDouble(twoDForm.format(((a))));

But i got the value like 190253.81 instead of that i want 190253.80

So what should i have to change for it ??

Answer 1

Because Math.round() Returns the closest int to the argument. The result is rounded to an integer by adding 1/2, taking the floor of the result, and casting the result to type int.
Use Math.floor()

Example

 public static double roundMyData(double Rval, int numberOfDigitsAfterDecimal) {
                  double p = (float)Math.pow(10,numberOfDigitsAfterDecimal);
              Rval = Rval * p;
              double tmp = Math.floor(Rval);
              System.out.println("~~~~~~tmp~~~~~"+tmp);
              return (double)tmp/p;
              }

Complete Source code

class ZiggyTest2{


        public static void main(String[] args) {  
             double num = 190253.80846153846;
              double round = roundMyData(num,2);
              System.out.println("Rounded data: " + round);
              }

              public static double roundMyData(double Rval, int numberOfDigitsAfterDecimal) {
                  double p = (float)Math.pow(10,numberOfDigitsAfterDecimal);
              Rval = Rval * p;
              double tmp = Math.floor(Rval);
              System.out.println("~~~~~~tmp~~~~~"+tmp);
              return (double)tmp/p;
              }
            }