Question

how to get the sorted NSArray from the NSArray that contains number string with two decimal points. Can anyone help me in this regard. Thanks in advance.

Answer 1

This should do the trick for you:

NSNumberFormatter *nf = [[NSNumberFormatter alloc] init];

NSArray *sortedArray = [unsortedArray sortedArrayUsingComparator:^(id obj1, id obj2) {
  if ([obj1 isKindOfClass:[NSString class]] && [obj2 isKindOfClass:[NSString class]]) {
    NSArray *obj1Components = [(NSString *)obj1 componentsSeparatedByString:@"."];
    NSArray *obj2Components = [(NSString *)obj2 componentsSeparatedByString:@"."];

    int highestCount = obj1Components.count;
    if (obj2Components.count > highestCount) {
        highestCount = obj2Components.count;
    }

    for (int i = 0; i < highestCount; i++) {

        // If the component does not exist, just make it 0
        NSNumber *num1 = [NSNumber numberWithInt:0];
        if (i < obj1Components.count) {
            num1 = [nf numberFromString:[obj1Components objectAtIndex:i]];
        }

        NSNumber *num2 = [NSNumber numberWithInt:0];
        if (i < obj2Components.count) {
            num2 = [nf numberFromString:[obj2Components objectAtIndex:i]];
        }

        int int1 = [num1 intValue];
        int int2 = [num2 intValue];

        if (int1 > int2) {
            return NSOrderedDescending;
        } else if (int2 > int1) {
            return NSOrderedAscending;
        }
    }

    // If we reach here, they're the same.
    return NSOrderedSame;

  } else {
      // They're not strings, so just say they're the same
      return NSOrderedSame;
  }
}];

[nf release];

It’ll take something like [“1.4.2”, “0.4.9”, “1”, “3.3.3.3.3”] and turn it into [“0.4.9”, “1”, “1.4.2”, “3.3.3.3.3”]