Question

How to implement the function ?

So it’ll output an array containing 2009-12-25 2009-12-26 2009-12-27 2009-12-28 2009-12-29 2009-12-30?

Answer 1

$startdate = strtotime("2009-12-25");
$enddate = strtotime("2009-12-30");
$steps = "1 day"; 

# Start
$date = $startdate;
while ($date <= $enddate)  
  {   echo date("Y-m-d", $date)."<br>";
      $date = strtotime ("+".$steps, $date); // can be slow with large arrays, 
                                             // you can also just add 60*60*24 seconds
                                             // to $date

   }