Question

how to include one page into another;

for example page 1 include page 2. page 2 does not show any content until it get the right arguments.

this is page 2 direct url call

www.mypage.com/execute.php?cmd=test

output is hello world

but when include the same page into page 1 like

include('execute.php?cmd=test');

or

$_GET['cmd']=$test;  
include('execute.php');

sorry but i think you guys didn’t understand me quite right. what im trying to do is, page 2 have some content which must be displayed only when its needed so therefore is have created a function in page 2 so I can call it. the content of must be viewed on page 1 by call. so i have tried to do which normally works ‘execute.php?cmd=test’ but its not this time

Answer 1

While I think I understand what you’re trying to do, it is the wrong approach. Use a third PHP script that both your pages will include. This way, you won’t have to hack the $_GET super global variable.

includes/somescript.php

// do something with $cmd
if ($cmd == 'test') echo 'Hello world';

page1.php

$cmd = 'test';
include 'includes/somescript.php';

page2.php

$cmd = $_GET['cmd'];
include 'includes/somescript.php';

Of course, the file includes/somescript.php should not just be executed like that, it should contain a function or a class with arguments that you include, then invoke from your pages. Up to you if you’re going OO or procedural with this.

Procedural

includes/somescript.php

function execute($cmd) {
   // ...
}

page1.php

include `includes/somescript.php';

execute('test');

Object Oriented

includes/somescript.php

class CommandHandler {
    public function execute($cmd) {
        //...
    }
}

page2.php

include `includes/somescript.php';

$h = new CommandHandler();
$h->execute($_GET['cmd']);