Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 7982267
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 4, 20262026-06-04T10:37:49+00:00 2026-06-04T10:37:49+00:00

How to make this syntax works : SELECT * FROM uploads, audienceuploadassociation WHERE uploads.member_id

  • 0

How to make this syntax works :

SELECT * 
FROM
  uploads,
  audienceuploadassociation 
WHERE 
  uploads.member_id = '1'
  AND uploads.member_school_id='1' 
  AND subject = 'Maths' 
  AND uploads.upload_id = audienceuploadassociation.upload_id 
  AND topic = 'Integers' 
  AND year IN(7, 8, 9) 
  AND audienceuploadassociation.audiencename LIKE (Parents, Teachers, Community)
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-04T10:37:51+00:00Added an answer on June 4, 2026 at 10:37 am

    Your LIKE clause is faulty. I suspect that you intend to use an IN() clause instead:

    AND audienceuploadassociation.audiencename IN ('Parents', 'Teachers', 'Community')
    

    If you are trying to match partial strings with LIKE, you need to OR them together in a () group, as in:

    AND (
      audienceuploadassociation.audiencename LIKE 'Parents%'
      OR audienceuploadassociation.audiencename LIKE 'Teachers%'
      OR audienceuploadassociation.audiencename LIKE 'Community%'
    )
    

    Note also, that the implicit join syntax you are using (comma-separated tables) is deprecated in favor of an explicit JOIN.

    SELECT
      uploads.*,
      audienceuploadassociation.*
    FROM
      /* Explicit JOIN  with ON clause */
      uploads
      JOIN audienceuploadassociation ON uploads.upload_id = audienceuploadassociation.upload_id 
    WHERE 
      uploads.member_id = '1'
      AND uploads.member_school_id='1' 
      AND subject = 'Maths' 
      AND topic = 'Integers' 
      AND year IN(7, 8, 9) 
      AND audienceuploadassociation.audiencename IN ('Parents', 'Teachers', 'Community')
    

    Finally, I would recommend explicitly naming the columns you want rather than doing SELECT *, so you get them in a deterministic order, and guard against the addition of other columns later that you don’t need in this query:

    SELECT 
      uploads.upload_id,
      uploads.other_column,
      uploads.topic,
      audienceuploadassociation.audiencename,
      ...
      ...
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I am trying this to make a select and it works just fine string
i would like to learn how to make PHP/CSS syntax generator. i assume this
I am using this query for pagination string selectStatement = SELECT * FROM (
To make this more clear, I'm going to put code samples: $file = fopen('filename.ext',
I make this program :: #include<stdio.h> char *raw_input(char *msg); main() { char *s; *s
I make this php program to access mysql data foreach ($arrayOfID as $ID) {
I make this post because a script of pure javascript tooltips, no jquery and
I need to make this function work everywhere, except IE6-7 $(function(){ window.scrollTo(0,300); }) Please
How do I make this so once the user inputs a number and presses
How can I make this input transparent? <input type=text class=foo> I've tried this but

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.