Question

How to mark 90 percentile in gnu plot. sample needed

plot [][] "fle.txt" using 1:2 with lines

This is how i plot the graph i want to mark the 90% in the graph
this is my data set

time(seconds)  frequency  cumulativeFrequency
10             2          2
11             6          8
12             8          16
13             10         26
14             7          33
15             5          38
16             5          43
17             4          47
18             2          49

Answer 1

I can’t see any way to do this in gnuplot by itself, but it’s not hard to do using python —

# percent90.py
import sys
def to_num(iterable):
    for line in iterable:
        columns = line.split()  # split into columns
        if not columns:  # empty line
            continue
        try:
            yield float(columns[1])  # This is a good number -- Yield it and keep going
        except ValueError:  # Not a number on the line
            pass            # just keep going -- do nothing
        except IndexError:
            print line

with open(sys.argv[1]) as fin:
     data = sorted(to_num(fin))

top_10 = data[int(len(data)*0.9):]  #top 10 percent of the data
print(top_10[0])

which you can call something like:

python percent90.py path/to/datafile

This will tell you where to place your mark. As for marking it, I would probably do something like this in gnuplot:

YVAL = `python percent90.py path/to/datafile`
set arrow 1 from graph 0,first YVAL to graph 1,first YVAL ls 1 nohead front