Question

How to open a context menu on click of menu button on android device? Can anyone help me please..

@Override  
public void onCreateContextMenu(ContextMenu menu, View v,ContextMenuInfo menuInfo) {  
    super.onCreateContextMenu(menu, v, menuInfo);  
    menu.setHeaderTitle("Select");  
    menu.add(0, v.getId(), 0, "Gmail");  
    menu.add(0, v.getId(), 0, "Facebook");
    menu.add(0, v.getId(), 0, "Twitter");  
}  

@Override  
public boolean onContextItemSelected(MenuItem item) {  
    if(item.getTitle()=="Gmail"){function1(item.getItemId());}  
    else if(item.getTitle()=="Facebook"){function2(item.getItemId());}  
    else if(item.getTitle()=="Twitter"){function3(item.getItemId());}  

    return true;  
}  

How open the above context menu on click of menu button ?

Answer 1

Are you sure you want to open context Menu on Click of Menu button?

Because, Context Menu is for a specific view,

A contextual menu offers actions that affect a specific item or context frame in the UI. You can provide a context menu for any view, but they are most often used for items in a ListView, GridView, or other view collections in which the user can perform direct actions on each item.

To show a context menu on long click, most clients will want to call registerForContextMenu(View) and override onCreateContextMenu(ContextMenu, View, ContextMenu.ContextMenuInfo).

For menu Button of device you can use an Options Menu

Update:

I never try this, but you can do something like,

1. Handle Menu button press event of device,

   public boolean onKeyUp(int keyCode, KeyEvent event) {
       if (keyCode == KeyEvent.KEYCODE_MENU) {
            // ........
        }
       return true;
    }
   

2. Put line inside it,

   this.openContextMenu(view); // Here view is reference for which you have a register contect menu..