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Home/ Questions/Q 7401049
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T04:21:51+00:00 2026-05-29T04:21:51+00:00

How to open a filename given in Main’s argv[] (say, D:\a.txt) by CreateFile API?

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How to open a filename given in Main’s argv[] (say, D:\a.txt) by CreateFile API?

CreateFile( ReadBuffer, GENERIC_READ, FILE_SHARE_READ, NULL, OPEN_EXISTING, 
                                FILE_ATTRIBUTE_NORMAL, NULL );
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  1. Editorial Team
    Editorial Team
    2026-05-29T04:21:54+00:00Added an answer on May 29, 2026 at 4:21 am

    It looks to me that your problem is simply that you are trying to call a function like this

    Connect(char *filename)
    {
        HANDLE hFile = CreateFile(filename, ...);
        ....
    }
    

    and don’t know how to get hold of the first command-line argument. Do it like this:

    int main(int argc, char *argv[])
    {
        if (argc != 2)
        {
            printf("Incorrect number of arguments supplied\n.")
            return 1;
        }
        Connect(argv[1]);
        .....
        return 0;
    }
    

    Note that argv is an array containing argc items where each item is of type char*. So you simply want the item at index 1. The item at index 0 is the process name.

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