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Home/ Questions/Q 6798561
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T18:44:42+00:00 2026-05-26T18:44:42+00:00

How to (or is it possible to) unpack a parameter pack with a numeric

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How to (or is it possible to) unpack a parameter pack with a numeric sequence? For example,

template <typename C, typename... T>
C* init_from_tuple(bp::tuple tpl)
{
   return new C{bp::extract<T>("magic"(tpl))...}; // <--
}

which the <-- line should expand to

   return new C{bp::extract<T0>(tpl[0]),
                bp::extract<T1>(tpl[1]),
                .....
                bp::extract<Tn>(tpl[n])};

where n == sizeof...(T) - 1.

The purpose is to create a __init__ function for Boost.Python which accepts a tuple with predefined types.

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  1. Editorial Team
    Editorial Team
    2026-05-26T18:44:43+00:00Added an answer on May 26, 2026 at 6:44 pm

    Actually, it is possible for the unpack operations to target two different packs of parameters at once (I think they need be of equal length). Here we would like a pack of types, and a pack of numbers.

    Something akin to:

    template <typename C, typename... T, size_t... N>
    C* init_from_tuple_impl(bp::tuple tpl) {
      return new C{ bp::extract<T>(tpl[N])... };
    }
    

    We “just” need to generate the pack of indices:

    template <size_t... N> struct Collection {};
    
    template <typename C> struct ExtendCollection;
    
    template <size_t... N>
    struct ExtendCollection< Collection<N...> > {
      typedef Collection<N..., sizeof...(N)> type;
    };
    
    template <typename... T>
    struct GenerateCollection;
    
    template <>
    struct GenerateCollection<> { typedef Collection<> type; };
    
    template <typename T0, typename... T>
    struct GenerateCollection<T0, T...> {
      typedef typename ExtendCollection<
        typename GenerateCollection<T...>::type
      >::type type;
    };
    

    And then use it:

    template <typename C, typename... T, size_t... N>
    C* init_from_tuple_impl(bp::tuple tpl, Collection<N...>) {
      return new C { bp::extract<T>(tpl[N])... };
    }
    
    template <typename C, typename... T>
    C* init_from_tuple(bp::tuple tpl) {
      typename GenerateCollection<T...>::type collection;
      return init_from_tuple_impl<C, T...>(tpl, collection);
    }
    

    In action at Ideone.

    We can witness the correctness by making a “mistake” in the implementation of init_from_tuple_impl (remove the new for example):

    template <typename C, typename... T, size_t... N>
    C* init_from_tuple_impl(bp::tuple tpl, Collection<N...>) {
      return C { bp::extract<T>(tpl[N])... };
    }
    

    In action at Ideone:

    prog.cpp: In function 'C* init_from_tuple_impl(bp::tuple, Collection<N ...>)
    [with
        C = bp::Object,
        T = {int, float, char},
        unsigned int ...N = {0u, 1u, 2u},
        bp::tuple = std::basic_string<char>
    ]':
    

    Exactly what we wanted 🙂

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