Question

How to pass a custom php.ini to phpunit?

The source uses

get_cfg_var 

instead of

ini_get

so unfortunately it doesn’t use values set by ini_set, -d option etc.

Only way to pass the value now is to use an additional php.ini. How do I pass that into phpunit?

Gory details:

I tried passing in with -d

phpunit --filter testgetdesc -d SIEF_VALIDATOR_DOC_ROOT="htdocs" 
--configuration tests/phpunit.xml tests/configHelperTest.php

public function testgetdesc() {
    echo get_cfg_var("SIEF_VALIDATOR_DOC_ROOT")."---test---";
}

It simply echoes “—test—“

The reason is this uses ini_set as well:

https://github.com/sebastianbergmann/phpunit/blob/master/PHPUnit/TextUI/Command.php

            case 'd': {
                $ini = explode('=', $option[1]);

                if (isset($ini[0])) {
                    if (isset($ini[1])) {
                        ini_set($ini[0], $ini[1]);
                    } else {
                        ini_set($ini[0], TRUE);
                    }
                }
            }

Also in the phpunit.xml, I have

<php>
  <ini name="SIEF_VALIDATOR_DOC_ROOT" value="bar"/>
</php>

which doesn’t work [and I don’t expect it to].

Answer 1

-d should work because PHPs get_cfg_var() function reads those:

$ php -d display.errors2=1 -r "echo get_cfg_var('display.errors2');"
1

To pass a custom ini setting (or alternatively the ini file with -c <file> to phpunit), invoke it configured:

$ php -c <file> -d setting=value $(which phpunit) <your-params>...

---

References/See as well:

• php --help, Command line options, Executing PHP files, get_cfg_var() function
• PHPUnit Docs: Command-Line Options, The XML Configuration File
• Shell: $( ... ) Command Substitution (Bash GNU Reference), which: Why not use "which"? What to use then?