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Home/ Questions/Q 7737623
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T08:03:03+00:00 2026-06-01T08:03:03+00:00

How to prevent further execution of class if something fails in constructor. ……..Worker.php………….. class

  • 0

How to prevent further execution of class if something fails in constructor.

........Worker.php..............
class Worker {

    public function __construct() {

        try {               
            $this->pheanstalk   = new Pheanstalk('127.0.0.1');
        }
        catch (Exception $e) {
            logFatal('Pheanstalk: '.$e->getMessage());
        }
    }
    .............
    .............
    .............
    .............
}

.

............processing.php..........
require_once ROOTPATH.'worker.php';

$worker = new worker();
$worker -> put($Data);
.............
.............
.............
.............

Now if the try block fails in the constructor i dont want to execute put() but rest of code should continue in processing.php

new Pheanstalk(‘127.0.0.1’); throws a exception which is caught by catch.

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  1. Editorial Team
    Editorial Team
    2026-06-01T08:03:04+00:00Added an answer on June 1, 2026 at 8:03 am

    Best solution is to catch the exception outside your class. Not only can you skip the put, logging errors is also not really the responsibility of that class anyway. Oh and Unit testing is easier too!

    class SomeClass
    {
        public function __construct() 
        {
            if ($somethingFails === true)
               throw new Exception();
        }
    }
    
    try {
        $instance = new SomeClass();
        $instance->put();
    } catch (Exception $exception) { 
        // Handle here
        logFatal('Pheanstalk: '.$e->getMessage());
    }
    

    If it’s another piece of application throwing the exception, and your constructor is wrapped around it. Consider catching the exception, and then throwing your own.

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