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Home/ Questions/Q 4251762
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T04:42:16+00:00 2026-05-21T04:42:16+00:00

How to randomly pick all the results, one by one (no repeats) from itertools.permutations(k)

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How to randomly pick all the results, one by one (no repeats) from itertools.permutations(k)? Or this: how to build a generator of randomized permutations? Something like shuffle(permutations(k)). I’m using Python 2.6.

Yeah, shuffle(r) could be used if r = list(permutations(k)), but such a list will take up too much time and memory when len(k) raises above 10.

Thanks.

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  1. Editorial Team
    Editorial Team
    2026-05-21T04:42:17+00:00Added an answer on May 21, 2026 at 4:42 am

    this gives the nth permutation of a list

    def perm_given_index(alist, apermindex):
        alist = alist[:]
        for i in range(len(alist)-1):
            apermindex, j = divmod(apermindex, len(alist)-i)
            alist[i], alist[i+j] = alist[i+j], alist[i]
        return alist
    

    where apermindex is between 0 and factorial(len(alist))

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