Question

How to render 2D shape of points in three.js? I didnt find any working geometry… I just need to make polygon of points that are in the same plane.

Shape isnt right for that as it supports only 2D coords and I need to use 3D points…

I am using the following code to create shape within the X,Y plane

 var squareShape = new THREE.Shape();
 squareShape.moveTo( 0,0 );
 squareShape.lineTo( 0, 50 );
 squareShape.lineTo( 20, 80 );
 squareShape.lineTo( 50, 50 );
 squareShape.lineTo( 0, 0 );

How to make in work it 3D world? Any solution? like:

squareShape.moveTo( 0,0,0 );
squareShape.lineTo( 0, 50, 50 );

etc

Answer 1

You need to create a geometry with the shapes’ vertices (after extraction) and use triangulation to make the faces.

The code should look something like this:

var geometry = new THREE.Geometry();
var shapePoints = shape.extractPoints();
var faces = THREE.Shape.Utils.triangulateShape(shapePoints.shape, shapePoints.holes);
for (var i = 0; i < shapePoints.shape.length; i++) {
    geometry.vertices.push(new THREE.Vector3(shapePoints.shape[i].x, 0, shapePoints.shape[i].y));
}
for (var i = 0; i < faces.length ; i++) {
    var a = faces[i][2] , b = faces[i][1] , c = faces[i][0] ;
    var v1 = shapePoints.shape[a], v2 = shapePoints.shape[b], v3 = shapePoints.shape[c];

    geometry.faces.push( new THREE.Face3(a, b, c) );    
    geometry.faceVertexUvs[0].push(
        [ new THREE.UV(v1.x ,v1.y ), new THREE.UV(v2.x, v2.y), new THREE.UV(v3.x, v3.y)]);
}
geometry.computeCentroids();
geometry.computeFaceNormals();