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Editorial Team
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Asked: 2026-06-15T12:51:39+00:00

How to replace the following correctly? NSString *stringURL = [NSString stringWithFormat:@http://192.168.1.183:8001/GetDocument.aspx?id=%@ & user=admin_document,self.index]; NSURL

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How to replace the following correctly?

NSString *stringURL = [NSString stringWithFormat:@"http://192.168.1.183:8001/GetDocument.aspx?id=%@ &  user=admin_document",self.index];
NSURL *targetURL = [NSURL URLWithString:stringURL];

I want to replace %@ with self.index.

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1 Answer

  1. Editorial Team

    Your problem is more likely the whitespace. Try removing it:

    NSString *stringURL = [NSString stringWithFormat:@"http://192.168.1.183:8001/GetDocument.aspx?id=%@&user=admin_document", self.index];
NSLog(@"URL:%@", stringURL); //You can print out to check
NSURL *targetURL = [NSURL URLWithString:stringURL];
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