Question

How to return user back to the page where he came from, after successful logout?
My logout function looks like that.

function logout()
{
global $db;
session_start();

if(isset($_SESSION['id']) || isset($_COOKIE['id'])) {
$db->query("update `users` 
            set `ckey`= '', `ctime`= '' 
            where `id`='$_SESSION[id]' OR  `id` = '$_COOKIE[id]'") or die($db->error);
}           

/************ Delete the sessions****************/
unset($_SESSION['id']);
unset($_SESSION['login']);
unset($_SESSION['level']);
unset($_SESSION['HTTP_USER_AGENT']);
session_unset();
session_destroy(); 

/* Delete the cookies*******************/
setcookie("id", '', time()-60*60*24*COOKIE_TIME_OUT, "/");
setcookie("login", '', time()-60*60*24*COOKIE_TIME_OUT, "/");
setcookie("key", '', time()-60*60*24*COOKIE_TIME_OUT, "/");

header("Location: ????");
}

Answer 1

It’s not perfect but you can use $_SERVER['HTTP_REFERER'] to get the page URI from where the user clicked on the “logout” link.