Question

How to run php file with parameter using notepad++

test.php

<?php 
    /* ------- 
        test.php
    ------- */
    if(!isset($_GET['file'])){
        exit;
    }
    $code=file_get_contents($_GET['file']);
    echo $code;

?>

---

demo_file.php —–$(FULL_CURRENT_PATH)

contents:

hello world

---

cd "D:\PHPnow-1.5.6\htdocs\zc_default\my_debug_fw"<br>
"d:\PHPnow-1.5.6\php-5.2.14-Win32\php.exe" "test.php" [what here?]

how to send “demo_file.php” as $_GET['file'] to test.php ?

The console finally should output:...... hello world

Answer 1

When utilizing PHP from the command line the arguments aren’t passed in as part of the $_GET superglobal. They’re passed in as part of the $_SERVER – superglobal where $_SERVER[‘argc’] is the number of arguments and $_SERVER[‘argv’] is an array of the argument values. $_SERVER[‘argv’][0] is the name of the php script and $_SERVER[‘argv’][1] would be the first argument.

    if($_SERVER['argc'] < 2){
        exit("Usage: php test.php <file>");
    }

    $code = file_get_contents($_SERVER['argv'][1]);

Per your example above…