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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T19:54:54+00:00 2026-05-26T19:54:54+00:00

How to sum all odd positioned elements in a list example [1,2,3,4,5,6,7,8,9] = 25

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How to sum all odd positioned elements in a list

example [1,2,3,4,5,6,7,8,9] = 25

odd([],0].
odd([Z],Z).
odd([X,Y|T], Sum+1):- odd(T,Sum).

but it return me 1+3+5+7+9.

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  1. Editorial Team
    Editorial Team
    2026-05-26T19:54:54+00:00Added an answer on May 26, 2026 at 7:54 pm

    What you construct when you write Sum+1 is a term with functor '+'/2 and arguments Sum and 1.

    In Prolog, when you want to calculate a sum, you need to use the predicate is/2.

    In your code, you should also add cuts to remove unnecessary choicepoints, and add X to the rest of the sum, not 1:

    odd([],0) :- !.
    odd([Z],Z) :- !.
    odd([X,_|T],Sum):- odd(T,Sum0), Sum is Sum0+X.
    

    Using an accumulator would allow you to make the code tail-recursive…

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