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Home/ Questions/Q 6763145
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T14:26:29+00:00 2026-05-26T14:26:29+00:00

How would I convert a dictionary of key value pairs into a single string?

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How would I convert a dictionary of key value pairs into a single string? Can you do this using LINQ aggregates? I’ve seen examples on doing this using a list of strings, but not a dictionary.

Input:

Dictionary<string, string> map = new Dictionary<string, string> { 
          {"A", "Alpha"},  
          {"B", "Beta"}, 
          {"G", "Gamma"}
};

Output:

  string result = "A:Alpha, B:Beta, G:Gamma";
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  1. Editorial Team
    Editorial Team
    2026-05-26T14:26:30+00:00Added an answer on May 26, 2026 at 2:26 pm

    This is the most concise way I can think of:

    var result = string.Join(", ", map.Select(m => m.Key + ":" + m.Value).ToArray());
    

    If you are using .NET 4+ you can drop the .ToArray():

    var result = string.Join(", ", map.Select(m => m.Key + ":" + m.Value));
    

    And if you are able to use the newish string interpolation language feature:

    var result = string.Join(", ", map.Select(m => $"{m.Key}:{m.Value}"));
    

    However, depending on your circumstances, this might be faster (although not very elegant):

    var result = map.Aggregate(new StringBuilder(),
        (a, b) => a.Append(", ").Append(b.Key).Append(":").Append(b.Value),
        (a) => a.Remove(0, 2).ToString());
    

    I ran each of the above with a varying number of iterations (10,000; 1,000,000; 10,000,000) on your three-item dictionary and on my laptop, the latter was on average 39% faster. On a dictionary with 10 elements, the latter was only about 22% faster.

    One other thing to note, simple string concatenation in my first example was about 38% faster than the string.Format() variation in mccow002’s answer, as I suspect it’s throwing in a little string builder in place of the concatenation, given the nearly identical performance metrics.

    To recreate the original dictionary from the result string, you could do something like this:

    var map = result.Split(',')
        .Select(p => p.Trim().Split(':'))
        .ToDictionary(p => p[0], p => p[1]);
    
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