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Home/ Questions/Q 7931733
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T20:48:38+00:00 2026-06-03T20:48:38+00:00

How would I do: FinancialStatements.objects.get(statement_id=statement_id) or SalesStatements.objects.get(statement_id=statement_id) The result will always yield one result.

  • 0

How would I do:

FinancialStatements.objects.get(statement_id=statement_id) 
    or SalesStatements.objects.get(statement_id=statement_id)

The result will always yield one result.

I ended up using the try/except route here:

    try:
        statement_object = FinancialStatements.objects.get(statement_id=statement_id)
    except FinancialStatements.DoesNotExist:
        statement_object = SalesStatements.objects.get(statement_id=statement_id)
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-03T20:48:40+00:00Added an answer on June 3, 2026 at 8:48 pm

    Why not simply do:

    result = (FinancialStatements.objects.filter(statement_id=statement_id) or
              SalesStatements.objects.filter(statement_id=statement_id))
    

    This should work, because filter returns a list – and an empty list if no entries match. An empty list evaluates to false in python’s boolean logic, e.g. try running:

    print [] or "hello"
    

    (Just as a check, compare print ["Hi"] or "hello")

    So, if the first query returns empty, the second will then be run. However, if the first matches anything, this will be result and the second query will be ignored.

    Addendum: result will then be of a list type – you’ll need to extract the (one and only) element with result[0].

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