Question

How would I do that?

According to PHP.net,

$a = "hi";
$hi = 2;
$$a; // returns 2

However, I need:

$i = 2;
$_POST['link$i'];  // I need this to return the same thing as $_POST['link2']

Here is how I have my code.

      for ($i = 1; $i <= 40; $i++)
      {
        if(!empty($link$i))
        {
        $link$i = mysql_real_escape_string($_POST['link$i']);
        mysql_query("
          INSERT INTO links (link, rimageid) VALUES
          ('".$link$i."', '".$id."') ");
        } else { }
      }

The reason I’m doing this is because I have a lot of text input fields posting their values to this file, and I’d like to define and insert each of their values via a for loop instead of manually inserting each single link into mysql.

Right now, I get:

Parse error: syntax error, unexpected T_VARIABLE, expecting ')' in C:\xampp\htdocs\new2.php on line 22

How would I go about doing this?
Thanks!

Answer 1

For array index concatenation, ok, but this code

for ($i = 1; $i <= 40; $i++)
      {
        if(!empty($link$i))
        {
        $link$i = mysql_real_escape_string($_POST['link$i']);
        mysql_query("
          INSERT INTO links (link, rimageid) VALUES
          ('".$link$i."', '".$id."') ");
        } else { }
      }

won’t work as you expect, i.e. name a variable like the result it’s not necessary, why would you want to do that? PHP doesn’t care about the variable name and if it’s coordinated with the result.

Just do:

for ($i = 1; $i <= 40; $i++)
      {
      if(!empty($_POST['link'.$i]))
      {
        $regular_variable_name = mysql_real_escape_string($_POST['link'.$i]);
        mysql_query("INSERT INTO links (link, rimageid) VALUES ('".$regular_variable_name."', '".$id."') ");
        } else { }
      }