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Home/ Questions/Q 141283
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Asked: May 11, 20262026-05-11T07:45:06+00:00 2026-05-11T07:45:06+00:00

How would I get my variables out of a vector? I can’t use the

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How would I get my variables out of a vector?

I can’t use the binary insertion operators or the equal operators.

Earlier, I declared a vector<someStruct> *vObj and allocated it, then returned the vObj and called it in this function:

vector<sameStruct> firstFunc();  for (unsigned int x = 0; x < v->size(); x++) {    v[x]; } 

when I debug it, v[x] now has the full contents of the original vector, as it did before without the subscript/index.

But I don’t think I’ve done anything to progress beyond that.

I just have about 4 variables inside my vector; when I debug it, it has the information that I need, but I can’t get to it.

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  1. 2026-05-11T07:45:06+00:00Added an answer on May 11, 2026 at 7:45 am

    As it is written v is a pointer to a vector of structs.

    When you index directly into v all you are doing is pointer arithmatic. v[x] is the vector of structs at position x (assuming that v is an array if it is just a single object at the end of the pointer then v[x] for x>0 is just garbage). This is because it is applying the [x] not to the vector pointed to by v but to the pointer v itself.

    You need to dereference the pointer and then index into the vector using something like:

    (*v)[x]; 

    At this point you have a reference to the object at the xth position of the vector to get at its member functions / variables use:

    (*v)[x].variable; 

    or

    (*v)[x].memberfunction(parameters); 

    If you do not want to dereference the vector then access the element within it you might try something like:

    v->at(x); v->at(x).variable; v->at(x).memberfunction; 

    This way you are accessing a member function of an object in exactly the same manner as when you called:

    v->size(); 

    I hope that this helps.

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