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Home/ Questions/Q 3672182
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T02:34:40+00:00 2026-05-19T02:34:40+00:00

How would I go about sorting in descending order, a List<Tuple<int, int>> using the

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How would I go about sorting in descending order, a List<Tuple<int, int>> using the first element of the tuple as the value that determines the order? It has to be in-place and I only know how to do it using LINQ which returns a new list.

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  1. Editorial Team
    Editorial Team
    2026-05-19T02:34:40+00:00Added an answer on May 19, 2026 at 2:34 am

    You just need to provide an IComparer<Tuple<int, int>> or a Comparison<Tuple<int, int>> to the List<T>.Sort method. The latter is probably easier to specify inline:

    list.Sort((x, y) => y.Item1.CompareTo(x.Item1));
    

    If you want to order by the first value and then the second value, it becomes a bit trickier, but still feasible. For example:

    list.Sort((x, y) => {
        int result = y.Item1.CompareTo(x.Item1);
        return result == 0 ? y.Item2.CompareTo(x.Item2) : result;
    });
    

    EDIT: I’ve now amended the above to sort in descending order. Note that the right way to do this is to reverse the order of the comparison (y to x instead of x to y). You must not just negate the return value of CompareTo – this will fail when CompareTo returns int.MinValue.

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